b-7/4+2/3b=19/12

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Solution for b-7/4+2/3b=19/12 equation: 



b-7/4+2/3b=19/12

We move all terms to the left:

b-7/4+2/3b-(19/12)=0



Domain of the equation: 3b!=0

b!=0/3

b!=0

b∈R



We add all the numbers together, and all the variables

b+2/3b-7/4-(+19/12)=0

We get rid of parentheses

b+2/3b-7/4-19/12=0

We calculate fractions

There is no solution for this equation

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