b-6(4b-2)=150

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Solution for b-6(4b-2)=150 equation: 



b-6(4b-2)=150

We move all terms to the left:

b-6(4b-2)-(150)=0

We multiply parentheses

b-24b+12-150=0

We add all the numbers together, and all the variables

-23b-138=0

We move all terms containing b to the left, all other terms to the right

-23b=138

b=138/-23

b=-6

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