b-5-3b=4(6b-4)-3(6-b)

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Solution for b-5-3b=4(6b-4)-3(6-b) equation: 



b-5-3b=4(6b-4)-3(6-b)

We move all terms to the left:

b-5-3b-(4(6b-4)-3(6-b))=0

We add all the numbers together, and all the variables

b-3b-(4(6b-4)-3(-1b+6))-5=0

We add all the numbers together, and all the variables

-2b-(4(6b-4)-3(-1b+6))-5=0



We calculate terms in parentheses: -(4(6b-4)-3(-1b+6)), so:

4(6b-4)-3(-1b+6)

We multiply parentheses

24b+3b-16-18

We add all the numbers together, and all the variables

27b-34

Back to the equation:

-(27b-34)



We get rid of parentheses

-2b-27b+34-5=0

We add all the numbers together, and all the variables

-29b+29=0

We move all terms containing b to the left, all other terms to the right

-29b=-29

b=-29/-29

b=1

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