b-3(b-3)=2b+5

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Solution for b-3(b-3)=2b+5 equation:


Simplifying
b + -3(b + -3) = 2b + 5

Reorder the terms:
b + -3(-3 + b) = 2b + 5
b + (-3 * -3 + b * -3) = 2b + 5
b + (9 + -3b) = 2b + 5

Reorder the terms:
9 + b + -3b = 2b + 5

Combine like terms: b + -3b = -2b
9 + -2b = 2b + 5

Reorder the terms:
9 + -2b = 5 + 2b

Solving
9 + -2b = 5 + 2b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-2b' to each side of the equation.
9 + -2b + -2b = 5 + 2b + -2b

Combine like terms: -2b + -2b = -4b
9 + -4b = 5 + 2b + -2b

Combine like terms: 2b + -2b = 0
9 + -4b = 5 + 0
9 + -4b = 5

Add '-9' to each side of the equation.
9 + -9 + -4b = 5 + -9

Combine like terms: 9 + -9 = 0
0 + -4b = 5 + -9
-4b = 5 + -9

Combine like terms: 5 + -9 = -4
-4b = -4

Divide each side by '-4'.
b = 1

Simplifying
b = 1

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