b-3(b+3)+4=b-7

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Solution for b-3(b+3)+4=b-7 equation: 



b-3(b+3)+4=b-7

We move all terms to the left:

b-3(b+3)+4-(b-7)=0

We multiply parentheses

b-3b-(b-7)-9+4=0

We get rid of parentheses

b-3b-b+7-9+4=0

We add all the numbers together, and all the variables

-3b+2=0

We move all terms containing b to the left, all other terms to the right

-3b=-2

b=-2/-3

b=2/3

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