b-2(4-b)=5

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Solution for b-2(4-b)=5 equation: 



b-2(4-b)=5

We move all terms to the left:

b-2(4-b)-(5)=0

We add all the numbers together, and all the variables

b-2(-1b+4)-5=0

We multiply parentheses

b+2b-8-5=0

We add all the numbers together, and all the variables

3b-13=0

We move all terms containing b to the left, all other terms to the right

3b=13

b=13/3

b=4+1/3

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