b-11+3(b+5)=7

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Solution for b-11+3(b+5)=7 equation: 



b-11+3(b+5)=7

We move all terms to the left:

b-11+3(b+5)-(7)=0

We add all the numbers together, and all the variables

b+3(b+5)-18=0

We multiply parentheses

b+3b+15-18=0

We add all the numbers together, and all the variables

4b-3=0

We move all terms containing b to the left, all other terms to the right

4b=3

b=3/4

b=3/4

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