b-1(4-8b)-2=2(b+11)

Solution for b-1(4-8b)-2=2(b+11) equation:

b-1(4-8b)-2=2(b+11)

We move all terms to the left:

b-1(4-8b)-2-(2(b+11))=0

We add all the numbers together, and all the variables

b-1(-8b+4)-(2(b+11))-2=0


We calculate terms in parentheses: -(2(b+11)), so:

2(b+11)

We multiply parentheses

2b+22

Back to the equation:

-(2b+22)


We get rid of parentheses

b-1(-8b+4)-2b-22-2=0

We add all the numbers together, and all the variables

-1b-1(-8b+4)-24=0

We move all terms containing b to the left, all other terms to the right

-1b-1(-8b+4)=24