b+90+3/2b+(2b-90)+(b+90)=540

Solution for b+90+3/2b+(2b-90)+(b+90)=540 equation:

b+90+3/2b+(2b-90)+(b+90)=540

We move all terms to the left:

b+90+3/2b+(2b-90)+(b+90)-(540)=0


Domain of the equation: 2b!=0

b!=0/2

b!=0

b∈R


We add all the numbers together, and all the variables

b+3/2b+(2b-90)+(b+90)-450=0

We get rid of parentheses

b+3/2b+2b+b-90+90-450=0

We multiply all the terms by the denominator


b*2b+2b*2b+b*2b-90*2b+90*2b-450*2b+3=0

Wy multiply elements

2b^2+4b^2+2b^2-180b+180b-900b+3=0

We add all the numbers together, and all the variables

8b^2-900b+3=0

a = 8; b = -900; c = +3;
Δ = b2-4ac
Δ = -9002-4·8·3
Δ = 809904
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{809904}=\sqrt{16*50619}=\sqrt{16}*\sqrt{50619}=4\sqrt{50619}$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-900)-4\sqrt{50619}}{2*8}=\frac{900-4\sqrt{50619}}{16}
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-900)+4\sqrt{50619}}{2*8}=\frac{900+4\sqrt{50619}}{16}
$