b+47=4b+5

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Solution for b+47=4b+5 equation: 



b+47=4b+5

We move all terms to the left:

b+47-(4b+5)=0

We get rid of parentheses

b-4b-5+47=0

We add all the numbers together, and all the variables

-3b+42=0

We move all terms containing b to the left, all other terms to the right

-3b=-42

b=-42/-3

b=+14

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