b+3b-10=2(2b-5)

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Solution for b+3b-10=2(2b-5) equation:


Simplifying
b + 3b + -10 = 2(2b + -5)

Reorder the terms:
-10 + b + 3b = 2(2b + -5)

Combine like terms: b + 3b = 4b
-10 + 4b = 2(2b + -5)

Reorder the terms:
-10 + 4b = 2(-5 + 2b)
-10 + 4b = (-5 * 2 + 2b * 2)
-10 + 4b = (-10 + 4b)

Add '10' to each side of the equation.
-10 + 10 + 4b = -10 + 10 + 4b

Combine like terms: -10 + 10 = 0
0 + 4b = -10 + 10 + 4b
4b = -10 + 10 + 4b

Combine like terms: -10 + 10 = 0
4b = 0 + 4b
4b = 4b

Add '-4b' to each side of the equation.
4b + -4b = 4b + -4b

Combine like terms: 4b + -4b = 0
0 = 4b + -4b

Combine like terms: 4b + -4b = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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