b+3/2b+(2b-90)+90+(b+45)=40

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Solution for b+3/2b+(2b-90)+90+(b+45)=40 equation: 


b in (-oo:+oo)

b+(3/2)*b+2*b+b-90+45+90 = 40 // - 40

b+(3/2)*b+2*b+b-90-40+45+90 = 0

11/2*b+5 = 0 // - 5

11/2*b = -5 // : 11/2

b = -5/11/2

b = -10/11

b = -10/11

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