b+3+2(b+3)=57

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Solution for b+3+2(b+3)=57 equation:


Simplifying
b + 3 + 2(b + 3) = 57

Reorder the terms:
b + 3 + 2(3 + b) = 57
b + 3 + (3 * 2 + b * 2) = 57
b + 3 + (6 + 2b) = 57

Reorder the terms:
3 + 6 + b + 2b = 57

Combine like terms: 3 + 6 = 9
9 + b + 2b = 57

Combine like terms: b + 2b = 3b
9 + 3b = 57

Solving
9 + 3b = 57

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-9' to each side of the equation.
9 + -9 + 3b = 57 + -9

Combine like terms: 9 + -9 = 0
0 + 3b = 57 + -9
3b = 57 + -9

Combine like terms: 57 + -9 = 48
3b = 48

Divide each side by '3'.
b = 16

Simplifying
b = 16

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