b+20/9=3

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Solution for b+20/9=3 equation: 



b+20/9=3

We move all terms to the left:

b+20/9-(3)=0

determiningTheFunctionDomain
b-3+20/9=0

We multiply all the terms by the denominator


b*9+20-3*9=0

We add all the numbers together, and all the variables

b*9-7=0

Wy multiply elements

9b-7=0

We move all terms containing b to the left, all other terms to the right

9b=7

b=7/9

b=7/9

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