b+20/2=12

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Solution for b+20/2=12 equation: 



b+20/2=12

We move all terms to the left:

b+20/2-(12)=0

determiningTheFunctionDomain
b-12+20/2=0

We add all the numbers together, and all the variables

b-2=0

We move all terms containing b to the left, all other terms to the right

b=2

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