b+2/b-4-b+6/b+3=1

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Solution for b+2/b-4-b+6/b+3=1 equation: 



b+2/b-4-b+6/b+3=1

We move all terms to the left:

b+2/b-4-b+6/b+3-(1)=0



Domain of the equation: b!=0

b∈R



We add all the numbers together, and all the variables

2/b+6/b-2=0

We multiply all the terms by the denominator


-2*b+2+6=0

We add all the numbers together, and all the variables

-2b+8=0

We move all terms containing b to the left, all other terms to the right

-2b=-8

b=-8/-2

b=+4

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