b+2/3+(2b+90)+90+(b+45)=540

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Solution for b+2/3+(2b+90)+90+(b+45)=540 equation: 



b+2/3+(2b+90)+90+(b+45)=540

We move all terms to the left:

b+2/3+(2b+90)+90+(b+45)-(540)=0

determiningTheFunctionDomain
b+(2b+90)+(b+45)+90-540+2/3=0

We add all the numbers together, and all the variables

b+(2b+90)+(b+45)-450+2/3=0

We get rid of parentheses

b+2b+b+90+45-450+2/3=0

We multiply all the terms by the denominator


b*3+2b*3+b*3+2+90*3+45*3-450*3=0

We add all the numbers together, and all the variables

b*3+2b*3+b*3-943=0

Wy multiply elements

3b+6b+3b-943=0

We add all the numbers together, and all the variables

12b-943=0

We move all terms containing b to the left, all other terms to the right

12b=943

b=943/12

b=78+7/12

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