b+2(b+5)=3(b-1)+3

Solution for b+2(b+5)=3(b-1)+3 equation:

Simplifying
b + 2(b + 5) = 3(b + -1) + 3

Reorder the terms:
b + 2(5 + b) = 3(b + -1) + 3
b + (5 * 2 + b * 2) = 3(b + -1) + 3
b + (10 + 2b) = 3(b + -1) + 3

Reorder the terms:
10 + b + 2b = 3(b + -1) + 3

Combine like terms: b + 2b = 3b
10 + 3b = 3(b + -1) + 3

Reorder the terms:
10 + 3b = 3(-1 + b) + 3
10 + 3b = (-1 * 3 + b * 3) + 3
10 + 3b = (-3 + 3b) + 3

Reorder the terms:
10 + 3b = -3 + 3 + 3b

Combine like terms: -3 + 3 = 0
10 + 3b = 0 + 3b
10 + 3b = 3b

Add '-3b' to each side of the equation.
10 + 3b + -3b = 3b + -3b

Combine like terms: 3b + -3b = 0
10 + 0 = 3b + -3b
10 = 3b + -3b

Combine like terms: 3b + -3b = 0
10 = 0

Solving
10 = 0

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.