b+2(b+2b)=4b

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Solution for b+2(b+2b)=4b equation: 



b+2(b+2b)=4b

We move all terms to the left:

b+2(b+2b)-(4b)=0

We add all the numbers together, and all the variables

b+2(+3b)-4b=0

We add all the numbers together, and all the variables

-3b+2(+3b)=0

We multiply parentheses

-3b+6b=0

We add all the numbers together, and all the variables

3b=0

b=0/3

b=0

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