b+2(b+1)=5

Solution for b+2(b+1)=5 equation:

Simplifying
b + 2(b + 1) = 5

Reorder the terms:
b + 2(1 + b) = 5
b + (1 * 2 + b * 2) = 5
b + (2 + 2b) = 5

Reorder the terms:
2 + b + 2b = 5

Combine like terms: b + 2b = 3b
2 + 3b = 5

Solving
2 + 3b = 5

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + 3b = 5 + -2

Combine like terms: 2 + -2 = 0
0 + 3b = 5 + -2
3b = 5 + -2

Combine like terms: 5 + -2 = 3
3b = 3

Divide each side by '3'.
b = 1

Simplifying
b = 1