b+2(7b-2)=-5(-5b-8)+b

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Solution for b+2(7b-2)=-5(-5b-8)+b equation: 



b+2(7b-2)=-5(-5b-8)+b

We move all terms to the left:

b+2(7b-2)-(-5(-5b-8)+b)=0

We multiply parentheses

b+14b-(-5(-5b-8)+b)-4=0



We calculate terms in parentheses: -(-5(-5b-8)+b), so:

-5(-5b-8)+b

We add all the numbers together, and all the variables

b-5(-5b-8)

We multiply parentheses

b+25b+40

We add all the numbers together, and all the variables

26b+40

Back to the equation:

-(26b+40)



We add all the numbers together, and all the variables

15b-(26b+40)-4=0

We get rid of parentheses

15b-26b-40-4=0

We add all the numbers together, and all the variables

-11b-44=0

We move all terms containing b to the left, all other terms to the right

-11b=44

b=44/-11

b=-4

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