b+12(b-4)=10b-3(2b-8)

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Solution for b+12(b-4)=10b-3(2b-8) equation: 



b+12(b-4)=10b-3(2b-8)

We move all terms to the left:

b+12(b-4)-(10b-3(2b-8))=0

We multiply parentheses

b+12b-(10b-3(2b-8))-48=0



We calculate terms in parentheses: -(10b-3(2b-8)), so:

10b-3(2b-8)

We multiply parentheses

10b-6b+24

We add all the numbers together, and all the variables

4b+24

Back to the equation:

-(4b+24)



We add all the numbers together, and all the variables

13b-(4b+24)-48=0

We get rid of parentheses

13b-4b-24-48=0

We add all the numbers together, and all the variables

9b-72=0

We move all terms containing b to the left, all other terms to the right

9b=72

b=72/9

b=8

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