b+(b-4)=(b+3)-(b+1)

Solution for b+(b-4)=(b+3)-(b+1) equation:

Simplifying
b + (b + -4) = (b + 3) + -1(b + 1)

Reorder the terms:
b + (-4 + b) = (b + 3) + -1(b + 1)

Remove parenthesis around (-4 + b)
b + -4 + b = (b + 3) + -1(b + 1)

Reorder the terms:
-4 + b + b = (b + 3) + -1(b + 1)

Combine like terms: b + b = 2b
-4 + 2b = (b + 3) + -1(b + 1)

Reorder the terms:
-4 + 2b = (3 + b) + -1(b + 1)

Remove parenthesis around (3 + b)
-4 + 2b = 3 + b + -1(b + 1)

Reorder the terms:
-4 + 2b = 3 + b + -1(1 + b)
-4 + 2b = 3 + b + (1 * -1 + b * -1)
-4 + 2b = 3 + b + (-1 + -1b)

Reorder the terms:
-4 + 2b = 3 + -1 + b + -1b

Combine like terms: 3 + -1 = 2
-4 + 2b = 2 + b + -1b

Combine like terms: b + -1b = 0
-4 + 2b = 2 + 0
-4 + 2b = 2

Solving
-4 + 2b = 2

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '4' to each side of the equation.
-4 + 4 + 2b = 2 + 4

Combine like terms: -4 + 4 = 0
0 + 2b = 2 + 4
2b = 2 + 4

Combine like terms: 2 + 4 = 6
2b = 6

Divide each side by '2'.
b = 3

Simplifying
b = 3