b+(b+45)+90+(2b-90)+3/2=540

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Solution for b+(b+45)+90+(2b-90)+3/2=540 equation: 



b+(b+45)+90+(2b-90)+3/2=540

We move all terms to the left:

b+(b+45)+90+(2b-90)+3/2-(540)=0

determiningTheFunctionDomain
b+(b+45)+(2b-90)+90-540+3/2=0

We add all the numbers together, and all the variables

b+(b+45)+(2b-90)-450+3/2=0

We get rid of parentheses

b+b+2b+45-90-450+3/2=0

We multiply all the terms by the denominator


b*2+b*2+2b*2+3+45*2-90*2-450*2=0

We add all the numbers together, and all the variables

b*2+b*2+2b*2-987=0

Wy multiply elements

2b+2b+4b-987=0

We add all the numbers together, and all the variables

8b-987=0

We move all terms containing b to the left, all other terms to the right

8b=987

b=987/8

b=123+3/8

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