b+(b+25)+3b=435

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Solution for b+(b+25)+3b=435 equation: 



b+(b+25)+3b=435

We move all terms to the left:

b+(b+25)+3b-(435)=0

We add all the numbers together, and all the variables

4b+(b+25)-435=0

We get rid of parentheses

4b+b+25-435=0

We add all the numbers together, and all the variables

5b-410=0

We move all terms containing b to the left, all other terms to the right

5b=410

b=410/5

b=82

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