b+(b+1)=122

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Solution for b+(b+1)=122 equation:


Simplifying
b + (b + 1) = 122

Reorder the terms:
b + (1 + b) = 122

Remove parenthesis around (1 + b)
b + 1 + b = 122

Reorder the terms:
1 + b + b = 122

Combine like terms: b + b = 2b
1 + 2b = 122

Solving
1 + 2b = 122

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + 2b = 122 + -1

Combine like terms: 1 + -1 = 0
0 + 2b = 122 + -1
2b = 122 + -1

Combine like terms: 122 + -1 = 121
2b = 121

Divide each side by '2'.
b = 60.5

Simplifying
b = 60.5

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