b+(a+b)+b+(3a-2b)=

Solution for b+(a+b)+b+(3a-2b)= equation:

Simplifying
b + (a + b) + b + (3a + -2b) = 0

Remove parenthesis around (a + b)
b + a + b + b + (3a + -2b) = 0

Remove parenthesis around (3a + -2b)
b + a + b + b + 3a + -2b = 0

Reorder the terms:
a + 3a + b + b + b + -2b = 0

Combine like terms: a + 3a = 4a
4a + b + b + b + -2b = 0

Combine like terms: b + b = 2b
4a + 2b + b + -2b = 0

Combine like terms: 2b + b = 3b
4a + 3b + -2b = 0

Combine like terms: 3b + -2b = 1b
4a + 1b = 0

Solving
4a + 1b = 0

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '-1b' to each side of the equation.
4a + 1b + -1b = 0 + -1b

Combine like terms: 1b + -1b = 0
4a + 0 = 0 + -1b
4a = 0 + -1b
Remove the zero:
4a = -1b

Divide each side by '4'.
a = -0.25b

Simplifying
a = -0.25b