b+(1/b+1)+2

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Solution for b+(1/b+1)+2 equation: 


D( b )

b = 0

b = 0

b = 0

b in (-oo:0) U (0:+oo)

b+1/b+1+2 = 0

1*b^1+1*b^-1+3*b^0 = 0

(1*b^2+3*b^1+1*b^0)/(b^1) = 0 // * b^2

b^1*(1*b^2+3*b^1+1*b^0) = 0

b^1

b^2+3*b+1 = 0

b^2+3*b+1 = 0

DELTA = 3^2-(1*1*4)

DELTA = 5

DELTA > 0

b = (5^(1/2)-3)/(1*2) or b = (-5^(1/2)-3)/(1*2)

b = (5^(1/2)-3)/2 or b = (-(5^(1/2)+3))/2

b in { (-(5^(1/2)+3))/2, (5^(1/2)-3)/2} 

b in { (-(5^(1/2)+3))/2, (5^(1/2)-3)/2 }

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