b*h=(64/3)*2 - solution

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Solution for bh=(64/3)2 equation:

x in (-oo:+oo)

b*h = 2*(64/3) // - 2*(64/3)

b*h-(2*(64/3)) = 0

b*h-128/3 = 0

b*h-128/3 = 0

x należy do R

x in (-oo:+oo)

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