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b(b-4.5)=9
We move all terms to the left:
b(b-4.5)-(9)=0
We multiply parentheses
b^2-4.5b-9=0
a = 1; b = -4.5; c = -9;
Δ = b2-4ac
Δ = -4.52-4·1·(-9)
Δ = 56.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4.5)-\sqrt{56.25}}{2*1}=\frac{4.5-\sqrt{56.25}}{2} $$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4.5)+\sqrt{56.25}}{2*1}=\frac{4.5+\sqrt{56.25}}{2} $
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