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b(b-4.4)=0
We multiply parentheses
b^2-4.4b=0
a = 1; b = -4.4; c = 0;
Δ = b2-4ac
Δ = -4.42-4·1·0
Δ = 19.36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4.4)-\sqrt{19.36}}{2*1}=\frac{4.4-\sqrt{19.36}}{2} $$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4.4)+\sqrt{19.36}}{2*1}=\frac{4.4+\sqrt{19.36}}{2} $
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