b(5px-3)=a(qz-4)

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Solution for b(5px-3)=a(qz-4) equation:


Simplifying
b(5px + -3) = a(qz + -4)

Reorder the terms:
b(-3 + 5px) = a(qz + -4)
(-3 * b + 5px * b) = a(qz + -4)
(-3b + 5bpx) = a(qz + -4)

Reorder the terms:
-3b + 5bpx = a(-4 + qz)
-3b + 5bpx = (-4 * a + qz * a)
-3b + 5bpx = (-4a + aqz)

Solving
-3b + 5bpx = -4a + aqz

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Reorder the terms:
4a + -1aqz + -3b + 5bpx = -4a + aqz + 4a + -1aqz

Reorder the terms:
4a + -1aqz + -3b + 5bpx = -4a + 4a + aqz + -1aqz

Combine like terms: -4a + 4a = 0
4a + -1aqz + -3b + 5bpx = 0 + aqz + -1aqz
4a + -1aqz + -3b + 5bpx = aqz + -1aqz

Combine like terms: aqz + -1aqz = 0
4a + -1aqz + -3b + 5bpx = 0

The solution to this equation could not be determined.

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