b(4.15)b=7

Solution for b(4.15)b=7 equation:

b(4.15)b=7

We move all terms to the left:

b(4.15)b-(7)=0

We multiply parentheses

4.15b^2-7=0

a = 4.15; b = 0; c = -7;
Δ = b2-4ac
Δ = 02-4·4.15·(-7)
Δ = 116.2
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{116.2}}{2*4.15}=\frac{0-\sqrt{116.2}}{8.3}
=-\frac{\sqrt{}}{8.3}
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{116.2}}{2*4.15}=\frac{0+\sqrt{116.2}}{8.3}
=\frac{\sqrt{}}{8.3}
$