b(2b+3)-2b(b-5)=6

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Solution for b(2b+3)-2b(b-5)=6 equation: 


Simplifying
b(2b + 3) + -2b(b + -5) = 6

Reorder the terms:
b(3 + 2b) + -2b(b + -5) = 6
(3 * b + 2b * b) + -2b(b + -5) = 6
(3b + 2b2) + -2b(b + -5) = 6

Reorder the terms:
3b + 2b2 + -2b(-5 + b) = 6
3b + 2b2 + (-5 * -2b + b * -2b) = 6
3b + 2b2 + (10b + -2b2) = 6

Reorder the terms:
3b + 10b + 2b2 + -2b2 = 6

Combine like terms: 3b + 10b = 13b
13b + 2b2 + -2b2 = 6

Combine like terms: 2b2 + -2b2 = 0
13b + 0 = 6
13b = 6

Solving
13b = 6

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Divide each side by '13'.
b = 0.4615384615

Simplifying
b = 0.4615384615

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