(5x-4)/(2)+(2x-7)/(6) - addition of fractions

Solution for the given fractions

• (5*x-4)/2 + (2*x-7)/6 = ?
• The common denominator of the two fractions is: 6
• (5*x-4)/2 = (3*(5*x-4))/(2*3) = (3*(5*x-4))/6
• (2*x-7)/6 = (1*(2*x-7))/(1*6) = (2*x-7)/6
• Fractions adjusted to a common denominator
• (5*x-4)/2 + (2*x-7)/6 = (3*(5*x-4))/6 + (2*x-7)/6
• (3*(5*x-4))/6 + (2*x-7)/6 = (3*(5*x-4)+2*x-7)/6
• (3*(5*x-4)+2*x-7)/6 = (3*(5*x-4)+2*x-7)/6

Solution for the given fractions

$ \frac{(5*x-4)}{2 }+ \frac{(2*x-7)}{6 }=? $

The common denominator of the two fractions is: 6

$ \frac{(5*x-4)}{2 }= \frac{(3*(5*x-4))}{(2*3)} = \frac{(3*(5*x-4))}{6} $

$ \frac{(2*x-7)}{6 }= \frac{(1*(2*x-7))}{(1*6)} = \frac{(2*x-7)}{6} $

Fractions adjusted to a common denominator

$ \frac{(5*x-4)}{2 }+ \frac{(2*x-7)}{6 }= \frac{(3*(5*x-4))}{6 }+ \frac{(2*x-7)}{6} $

$ \frac{(3*(5*x-4))}{6 }+ \frac{(2*x-7)}{6 }= \frac{(3*(5*x-4)+2*x-7)}{6} $

$ \frac{(3*(5*x-4)+2*x-7)}{6 }= \frac{(3*(5*x-4)+2*x-7)}{6} $

$ $

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