abs(z-3i)=5

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Solution for abs(z-3i)=5 equation: 


Simplifying
abs(z + -3i) = 5

Reorder the terms:
abs(-3i + z) = 5
(-3i * abs + z * abs) = 5
(-3abis + absz) = 5

Solving
-3abis + absz = 5

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Reorder the terms:
-5 + -3abis + absz = 5 + -5

Combine like terms: 5 + -5 = 0
-5 + -3abis + absz = 0

The solution to this equation could not be determined.

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