abs(z+i)+abs(z+4i)=4

Solution for abs(z+i)+abs(z+4i)=4 equation:

Simplifying
abs(z + i) + abs(z + 4i) = 4

Reorder the terms:
abs(i + z) + abs(z + 4i) = 4
(i * abs + z * abs) + abs(z + 4i) = 4
(abis + absz) + abs(z + 4i) = 4

Reorder the terms:
abis + absz + abs(4i + z) = 4
abis + absz + (4i * abs + z * abs) = 4
abis + absz + (4abis + absz) = 4

Reorder the terms:
abis + 4abis + absz + absz = 4

Combine like terms: abis + 4abis = 5abis
5abis + absz + absz = 4

Combine like terms: absz + absz = 2absz
5abis + 2absz = 4

Solving
5abis + 2absz = 4

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Reorder the terms:
-4 + 5abis + 2absz = 4 + -4

Combine like terms: 4 + -4 = 0
-4 + 5abis + 2absz = 0

The solution to this equation could not be determined.