abs(z+2i)-abs(z-2i)=4

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Solution for abs(z+2i)-abs(z-2i)=4 equation: 


Simplifying
abs(z + 2i) + -1abs(z + -2i) = 4

Reorder the terms:
abs(2i + z) + -1abs(z + -2i) = 4
(2i * abs + z * abs) + -1abs(z + -2i) = 4
(2abis + absz) + -1abs(z + -2i) = 4

Reorder the terms:
2abis + absz + -1abs(-2i + z) = 4
2abis + absz + (-2i * -1abs + z * -1abs) = 4
2abis + absz + (2abis + -1absz) = 4

Reorder the terms:
2abis + 2abis + absz + -1absz = 4

Combine like terms: 2abis + 2abis = 4abis
4abis + absz + -1absz = 4

Combine like terms: absz + -1absz = 0
4abis + 0 = 4
4abis = 4

Solving
4abis = 4

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Divide each side by '4bis'.
a = b-1i-1s-1

Simplifying
a = b-1i-1s-1

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