abs(y)=(2-x)/9

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Solution for abs(y)=(2-x)/9 equation: 


x in (-oo:+oo)

t_1 = abs(y)

t_1-((2-x)/9) = 0

(-1*(2-x))/9+t_1 = 0

(-1*(2-x))/9+(9*t_1)/9 = 0

9*t_1-1*(2-x) = 0

9*t_1+x-2 = 0

(9*t_1+x-2)/9 = 0

(9*t_1+x-2)/9 = 0 // * 9

9*t_1+x-2 = 0

9*t_1+x-2 = 0 // - 9*t_1-2

x = -(9*t_1-2)

x = 2-(9*t_1)

x = 2-(9*abs(y))

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