abs(x+3)+abs(4-x)=7

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Solution for abs(x+3)+abs(4-x)=7 equation:


Simplifying
abs(x + 3) + abs(4 + -1x) = 7

Reorder the terms:
abs(3 + x) + abs(4 + -1x) = 7
(3 * abs + x * abs) + abs(4 + -1x) = 7
(3abs + absx) + abs(4 + -1x) = 7
3abs + absx + (4 * abs + -1x * abs) = 7
3abs + absx + (4abs + -1absx) = 7

Reorder the terms:
3abs + 4abs + absx + -1absx = 7

Combine like terms: 3abs + 4abs = 7abs
7abs + absx + -1absx = 7

Combine like terms: absx + -1absx = 0
7abs + 0 = 7
7abs = 7

Solving
7abs = 7

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Divide each side by '7bs'.
a = b-1s-1

Simplifying
a = b-1s-1

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