abs(3x+1)=abs(3x-5)

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Solution for abs(3x+1)=abs(3x-5) equation:


Simplifying
abs(3x + 1) = abs(3x + -5)

Reorder the terms:
abs(1 + 3x) = abs(3x + -5)
(1 * abs + 3x * abs) = abs(3x + -5)
(1abs + 3absx) = abs(3x + -5)

Reorder the terms:
1abs + 3absx = abs(-5 + 3x)
1abs + 3absx = (-5 * abs + 3x * abs)
1abs + 3absx = (-5abs + 3absx)

Add '-3absx' to each side of the equation.
1abs + 3absx + -3absx = -5abs + 3absx + -3absx

Combine like terms: 3absx + -3absx = 0
1abs + 0 = -5abs + 3absx + -3absx
1abs = -5abs + 3absx + -3absx

Combine like terms: 3absx + -3absx = 0
1abs = -5abs + 0
1abs = -5abs

Solving
1abs = -5abs

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '5abs' to each side of the equation.
1abs + 5abs = -5abs + 5abs

Combine like terms: 1abs + 5abs = 6abs
6abs = -5abs + 5abs

Combine like terms: -5abs + 5abs = 0
6abs = 0

Divide each side by '6'.
abs = 0

Simplifying
abs = 0

The solution to this equation could not be determined.

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