a=9/5(h-42)

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Solution for a=9/5(h-42) equation: 


x in (-oo:+oo)

a = (9/5)*(h-42) // - (9/5)*(h-42)

a-((9/5)*(h-42)) = 0

(-9/5)*(h-42)+a = 0

a-9/5*(h-42) = 0

a-9/5*(h-42) = 0

a-9/5*h+378/5 = 0

a-9/5*h+378/5 = 0

x belongs to the empty set

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