a=7+12a/5+4a

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Solution for a=7+12a/5+4a equation: 



a=7+12a/5+4a

We move all terms to the left:

a-(7+12a/5+4a)=0



Domain of the equation: 5+4a)!=0

We move all terms containing a to the left, all other terms to the right

4a)!=-5

a!=-5/1

a!=-5

a∈R



We add all the numbers together, and all the variables

a-(4a+12a/5+7)=0

We get rid of parentheses

a-4a-12a/5-7=0

We multiply all the terms by the denominator


a*5-4a*5-12a-7*5=0

We add all the numbers together, and all the variables

-12a+a*5-4a*5-35=0

Wy multiply elements

-12a+5a-20a-35=0

We add all the numbers together, and all the variables

-27a-35=0

We move all terms containing a to the left, all other terms to the right

-27a=35

a=35/-27

a=-1+8/27

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