a=1/2(2a)

Solution for a=1/2(2a) equation:

a=1/2(2a)

We move all terms to the left:

a-(1/2(2a))=0


Domain of the equation: 22a)!=0

a!=0/1

a!=0

a∈R


We add all the numbers together, and all the variables

a-(+1/22a)=0

We get rid of parentheses

a-1/22a=0

We multiply all the terms by the denominator


a*22a-1=0

Wy multiply elements

22a^2-1=0

a = 22; b = 0; c = -1;
Δ = b2-4ac
Δ = 02-4·22·(-1)
Δ = 88
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{88}=\sqrt{4*22}=\sqrt{4}*\sqrt{22}=2\sqrt{22}$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{22}}{2*22}=\frac{0-2\sqrt{22}}{44}
=-\frac{2\sqrt{22}}{44}
=-\frac{\sqrt{22}}{22}
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{22}}{2*22}=\frac{0+2\sqrt{22}}{44}
=\frac{2\sqrt{22}}{44}
=\frac{\sqrt{22}}{22}
$