a=-33a2

Solution for a=-33a2 equation:

a=-33a^2

We move all terms to the left:

a-(-33a^2)=0

We get rid of parentheses

33a^2+a=0

a = 33; b = 1; c = 0;
Δ = b2-4ac
Δ = 12-4·33·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-1}{2*33}=\frac{-2}{66}
=-1/33
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+1}{2*33}=\frac{0}{66}
=0
$