a=(b-c)/a

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Solution for a=(b-c)/a equation: 


x in (-oo:+oo)

a = (b-c)/a // - (b-c)/a

a-((b-c)/a) = 0

(-1*(b-c))/a+a = 0

(-1*(b-c))/a+(a^2)/a = 0

a^2-1*(b-c) = 0

a^2-b+c = 0

(a^2-b+c)/a = 0

(a^2-b+c)/a = 0 // * a

a^2-b+c = 0

x belongs to the empty set

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