a=(b-c)/4

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Solution for a=(b-c)/4 equation:


x in (-oo:+oo)

a = (b-c)/4 // - (b-c)/4

a-((b-c)/4) = 0

(-1*(b-c))/4+a = 0

(-1*(b-c))/4+(4*a)/4 = 0

4*a-1*(b-c) = 0

4*a-b+c = 0

(4*a-b+c)/4 = 0

(4*a-b+c)/4 = 0 // * 4

4*a-b+c = 0

x belongs to the empty set

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