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a2-8a-11=0
We add all the numbers together, and all the variables
a^2-8a-11=0
a = 1; b = -8; c = -11;
Δ = b2-4ac
Δ = -82-4·1·(-11)
Δ = 108
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{108}=\sqrt{36*3}=\sqrt{36}*\sqrt{3}=6\sqrt{3}$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-6\sqrt{3}}{2*1}=\frac{8-6\sqrt{3}}{2} $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+6\sqrt{3}}{2*1}=\frac{8+6\sqrt{3}}{2} $
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