a2-28a+52=0

Solution for a2-28a+52=0 equation:

a2-28a+52=0

We add all the numbers together, and all the variables

a^2-28a+52=0

a = 1; b = -28; c = +52;
Δ = b2-4ac
Δ = -282-4·1·52
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{576}=24$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-28)-24}{2*1}=\frac{4}{2}
=2
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-28)+24}{2*1}=\frac{52}{2}
=26
$