a2+432-42a=0

Solution for a2+432-42a=0 equation:

a2+432-42a=0

We add all the numbers together, and all the variables

a^2-42a+432=0

a = 1; b = -42; c = +432;
Δ = b2-4ac
Δ = -422-4·1·432
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-42)-6}{2*1}=\frac{36}{2}
=18
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-42)+6}{2*1}=\frac{48}{2}
=24
$